解x属于[0,π]即0≤x≤π即0≤2x≤2π即π/3≤2x+π/3≤2π+π/3=7π/3即当π/3≤2x+π/3≤π/2时y=sin(2x+π/3)是增函数此时0≤x≤π/12或当3π/2≤2x+π/3≤7π/3时y=sin(2x+π/3)是增函数此时7π/12≤x≤π即单调增区间是{x/0≤x≤π/12}和{x/7π/12≤x≤π}
