复数(1+i分之根号2)^20的值等于?

过程详细点
2025-12-14 10:15:44
推荐回答(2个)
回答1:

[√2/(1+i)]^2=2/(2i)=1/i(1/i)^2=-1[√2/(1+i)]^20=(-1)^5=-1

回答2:

(1+√2/i)^20=(1-√2i)^20