x²≥0x²-9所以√x²-9<√x²-6方程无解
sinq/sin(q/2)=8/52sin(q/2)cos(q/2)/sin(q/2)=8/5cos(q/2)=4/500所以sin(q/2)=3/5sinq=2sin(q/2)cos(q/2)=24/25cosq=cos²(q/2)-sin²(q/2)=7/25tanq=sinq/cosq=24/7tan2q=2tanq/(1-tan²q)=(48/7)/(1-24²/7²)=-336/527
0所以sin(q/2)=3/5sinq=2sin(q/2)cos(q/2)=24/25cosq=cos²(q/2)-sin²(q/2)=7/25tanq=sinq/cosq=24/7tan2q=2tanq/(1-tan²q)=(48/7)/(1-24²/7²)=-336/527
所以sin(q/2)=3/5sinq=2sin(q/2)cos(q/2)=24/25cosq=cos²(q/2)-sin²(q/2)=7/25tanq=sinq/cosq=24/7tan2q=2tanq/(1-tan²q)=(48/7)/(1-24²/7²)=-336/527